Constant velocity implies no acceleration

Category:

Description

Constant velocity implies no acceleration

 

V = a * r2

VA = 0.25* 1002= 2500m/s

VB = 0.25 * 962 = 2304 m/s

 

FAg,x = mAgsin 300

                = 10 * 9.8 * sin 300

                = 49 N

FBg,x = mBgsin 300

                = 8 * 9.8 * sin 300

                = 39.2 N

mAgsin 300 – T = mAa

49 – T = 10a

T – mBgsin 300= mBa

T – 39.2 = 8a

49 – T + T – 39.2 = 10a + 8a

9.8 = 18a

The acceleration of each block is, a = 0.544 m/s2

Tension, T = 49 – 10 * 0.544 = 43.56 N

 

 

 

  1. T = m ( v2/ r + g cosθ)

At A θ = 00

T = m ( v2/ r + g cosθ) = 380 lb

At C θ = 1800

T = m ( v2/ r – g cosθ) = 80 lb

At B θ = 900

 

120 ( v2/ 3600 + 9.8) = 380

V = – 154.53 m/s

 

80 = 120 ( v2/ 3600 – 9.8 )

V = 194.11 m/s

V average = 39.58 m/s

At point B

T = 120 ( 39.582 / 3600 + 9.8 cos 90)

= 52. 2192 lb